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So, the equation is then, \[\begin4\left( \right) 2\left( x \right) & = 72\ 16x 2x & = 72\ 18x & = 72\ x & = 4\end\] So, it looks like the height of the set of shelves should be 4 feet. First, let’s define \(p\) to be the cost that the store paid for the calculator. This means that 0.15\(p\) has been added on to the original price (\(p\)) to get the amount the calculator is being sold for.Note however that we haven’t actually answered the question however. This means that we also need the width of the set of shelves. In other words, we have the following equation \[p 0.15p = 78.50\] that we need to solve for \(p\).
In a certain Algebra class there is a total of 350 possible points.
These points come from 5 homework sets that are worth 10 points each and 3 hour exams that are worth 100 points each.
We now need to discuss the section that most students hate.
We need to talk about applications to linear equations.
The standard formula that we will be using here is \[ = \times \] All of the problems that we’ll be doing in this set of examples will use this to one degree or another and often more than once as we will see.
Two cars are 500 miles apart and moving directly towards each other.We will first define \(x\) to be the height of the set of shelves.This means that 4\(x\) is width of the set of shelves.\[\frac = \] Since we are using the standard scale if the grade percentage is 0.9 or higher the student will get an A.Likewise, if the grade percentage is between 0.8 and 0.9 the student will get a B.Note as well that at this point it is assumed that you are capable of solving fairly simple linear equations and so not a lot of detail will be given for the actual solution stage.The point of this section is more on the set up of the equation than the solving of the equation. Due to the nature of the mathematics on this site it is best views in landscape mode.If your device is not in landscape mode many of the equations will run off the side of your device (should be able to scroll to see them) and some of the menu items will be cut off due to the narrow screen width.We know that the total possible points is 350 and the student has a total points (including the third exam) of, \[4 8 7 7 9 78 83 p = 196 p\] The smallest possible percentage for an A is 0.9 and so if \(p\) is the minimum required score on the third exam for an A we will have the following equation.\[\frac = 0.9\] This is a linear equation that we will need to solve for \(p\).